Bellator Kenai Shifter
Posts : 56 Join date : 20140217
 Subject: My Things  Noooo Touchy! Mon Mar 02, 2015 8:15 pm  
 For KenaiBear:POSTING TEMPLATE. Writing will go here. Please feel free to use this, if you want to. 

Dominus Demetri Admin
Posts : 172 Join date : 20130519 Location : Wichita, Kansas
Character sheet Rank: Dominus
 Subject: Re: My Things  Noooo Touchy! Mon Mar 02, 2015 11:03 pm  
 For Demetri: where my demons hide But with the beast inside A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the xaxis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x?
We have, for constant acceleration, the relations a = ( V  v ) / t and x = ½ ( V + v ) t. Here v is the particle's speed at t = 0 and V is its speed at time t. The the work done is W = F x = m a x = m ( ( V  v ) / t ) ( ½ ( V + v ) ) t = ½ m V²  ½ m v².
We call onehalf the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K = ½ m v². We may then state the above equation in this way:
The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.
A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the xaxis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x?
We have, for constant acceleration, the relations a = ( V  v ) / t and x = ½ ( V + v ) t. Here v is the particle's speed at t = 0 and V is its speed at time t. The the work done is W = F x = m a x = m ( ( V  v ) / t ) ( ½ ( V + v ) ) t = ½ m V²  ½ m v².
We call onehalf the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K = ½ m v². We may then state the above equation in this way:
The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle. There’s nowhere we can hide 

Dominus Demetri Admin
Posts : 172 Join date : 20130519 Location : Wichita, Kansas
Character sheet Rank: Dominus
 Subject: Re: My Things  Noooo Touchy! Tue Mar 03, 2015 12:25 am  
 For my Favorite Werewolf:
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 Subject: Re: My Things  Noooo Touchy!  
 
